7x^2+49x-149=0

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Solution for 7x^2+49x-149=0 equation:



7x^2+49x-149=0
a = 7; b = 49; c = -149;
Δ = b2-4ac
Δ = 492-4·7·(-149)
Δ = 6573
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{6573}}{2*7}=\frac{-49-\sqrt{6573}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{6573}}{2*7}=\frac{-49+\sqrt{6573}}{14} $

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